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80x^2-159268x-23892=0
a = 80; b = -159268; c = -23892;
Δ = b2-4ac
Δ = -1592682-4·80·(-23892)
Δ = 25373941264
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25373941264}=159292$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-159268)-159292}{2*80}=\frac{-24}{160} =-3/20 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-159268)+159292}{2*80}=\frac{318560}{160} =1991 $
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